Find the factors of x2-4 y2-4 y-4 x y-2 x-8 are-A- undefinedB- undefinedC- undefinedD- undefined

x^2 +4y^2 +4y 4xy 2x 8 x^2 +4y^2 +4y 4xy 2x 8 ⇒ (x 2y)^2+4y 2x 8 ⇒ (x 2y)^2 2(x 2y) 8 ⇒ (x 2y)^2 4(x 2y)+2(x 2y) 8 ⇒ (x 2y)[(x 2y) 4]+2[(x 2y) 4] ⇒ (x 2y+2) ...

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Byju's Answer

Standard IX

Mathematics

Perfect Square Trinomials

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Question

Find the factors of $x^{2} + 4 y^{2} + 4 y - 4 x y - 2 x - 8$ are?

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Solution

$x^{2} + 4 y^{2} + 4 y - 4 x y - 2 x - 8$
$x^{2} + 4 y^{2} + 4 y - 4 x y - 2 x - 8 \Rightarrow (x - 2 y)^{2} + 4 y - 2 x - 8 \Rightarrow (x - 2 y)^{2} - 2 (x - 2 y) - 8 \Rightarrow (x - 2 y)^{2} - 4 (x - 2 y) + 2 (x - 2 y) - 8 \Rightarrow (x - 2 y) [(x - 2 y) - 4] + 2 [(x - 2 y) - 4] \Rightarrow (x - 2 y + 2) (x - 2 y - 4)$ .

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Find the factors of x2+4y2+4y−4xy−2x−8 are?

x2+4y2+4y−4xy−2x−8 x2+4y2+4y−4xy−2x−8⇒(x−2y)2+4y−2x−8⇒(x−2y)2−2(x−2y)−8⇒(x−2y)2−4(x−2y)+2(x−2y)−8⇒(x−2y)[(x−2y)−4]+2[(x−2y)−4]⇒(x−2y+2)(x−2y−4).

Find the factors of $x^{2} + 4 y^{2} + 4 y - 4 x y - 2 x - 8$ are?