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B
a can take only three values
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C
a can be any integer
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D
a is a negative integer
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Solution
The correct options are A
a must be 2
B
a can take only three values
Let p(x)=(x3+2x2+2x+1) be the given polynomial. By observation, we can see that by putting (x=−1)p(x)=0 ∴x=−1 is the root of p(x) ⇒(x+1) is a factor of p(x) To find the other factor, we perform long division of p(x) by (x+1), x+1x2+x+1√x3+2x2+2x+1x3+x2−−¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯x2+2xx2+x−−¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯x+1x+1−−¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯0 ∴ The two factors of p(x) are (x+1) and (x2+x+1).