wiz-icon
MyQuestionIcon
MyQuestionIcon
4
You visited us 4 times! Enjoying our articles? Unlock Full Access!
Question

Find the factors of x3+2x2+2x+1.

A
(x+1) and (x2+x+1)
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B
(x+1) and (x2x+1)
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
(2x+1) and (x2+x+1)
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
(x+1) and (x2+3x+1)
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is A (x+1) and (x2+x+1)
Let p(x)=(x3+2x2+2x+1) be the given polynomial.

Substitute (x=1):
p(1)=(1)3+2×(1)2+2×(1)+1
p(1)=0
x=1 is a root of p(x)
(x+1) is a factor of p(x) by factor theorem.

To find the other factor, divide p(x) by (x+1),
x+1x2+x+1x3+2x2+2x+1 x3+x2 () () ¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯ x2+2x x2+x () () ¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯ x+1 x+1 () () ¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯ 0

The two factors of p(x) are (x+1) and (x2+x+1).

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Factorisation of Polynomials-Factor Theorem
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon