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Question

Find the factors of x3+2x2+2x+1.

A
(x+1) and (x2+x+1)
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B
(x+1) and (x2x+1)
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C
(2x+1) and (x2+x+1)
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D
(x+1) and (x2+3x+1)
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Solution

The correct option is A (x+1) and (x2+x+1)
Let p(x)=(x3+2x2+2x+1) be the given polynomial.

Substitute (x=1):
p(1)=(1)3+2×(1)2+2×(1)+1
p(1)=0
x=1 is a root of p(x)
(x+1) is a factor of p(x) by factor theorem.

To find the other factor, divide p(x) by (x+1),
x+1x2+x+1x3+2x2+2x+1 x3+x2 () () ¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯ x2+2x x2+x () () ¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯ x+1 x+1 () () ¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯ 0

The two factors of p(x) are (x+1) and (x2+x+1).

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