Find the factors of $y^{2} - 7 y + 12$ .

Open in App

Solution

$y^{2} - 7 y + 12$
$y^{2} - 3 y - 4 y + 12$
$y (y - 3) - y (y - 3)$
$(y - 3) (y - 4)$
$∴$ $y = 3, 4$

Suggest Corrections

Similar questions

Q. Factorize:

y^{2} + 7 y + 12

Factorize the following

y^{2} + 7 y + 12

Q. One of the factor of

Y^{2} - 7 Y + 12

Q. Find the factors.

(2) y² + 7y – 44

Find the equation of family of circles through the intersection of $x^{2} + y^{2} - 6 x + 2 y + 4 = 0$ and $x^{2} + y^{2} + 2 x - 4 y - 6 = 0$ whose center lies on $y = x .$

Join BYJU'S Learning Program

Find the factors of y2−7y+12.

y2−7y+12y2−3y−4y+12y(y−3)−y(y−3)(y−3)(y−4)∴ y=3,4

Find the factors of $y^{2} - 7 y + 12$ .

$y^{2} - 7 y + 12$
$y^{2} - 3 y - 4 y + 12$
$y (y - 3) - y (y - 3)$
$(y - 3) (y - 4)$
$∴$ $y = 3, 4$