Find the first $3$ terms of a G.P. if $a = 4$ and $r = 2$ .

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Solution

$T_{1} = a = 4 T_{2} = a r = 4 \times 2 = 8 T_{3} = a r^{2} = 4 \times 2^{2} = 16$
$∴$ The first three terms of the G.P. are $4, 8, 16$ .

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