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Question

Find the first five terms of the sequence specified by the recursion formula
ak+1=ak+3, if a1=7.

A
7,10,13,16,19
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B
6,9,12,15,18
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C
8,11,14,17,20
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D
5,8,11,14,17
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Solution

The correct option is A 7,10,13,16,19
Given ak+1=ak+3 and a1=7
So a2=a1+3=7+3=10
a3=a2+3=10+3=13
a4=a3+3=13+3=16
a5=a4+3=16+3=19

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