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Question

Find the first three terms of the sequence whose n th term is 2n+3.

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Solution

Here, Tn=2n+3
To find, T1, substitute n=1 in Tn=2n+3
T1=2(1)+3=2+3=5
To find T2, substitute n=2 in Tn=2n+3
T2=2(2)+3=4+3=7
Similarly, T3=2(3)+3=6+3=9
The first three terms of the sequence are 5,7,9.

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