Find the first three terms of the sequence whose nth term is 2n+3.
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Solution
Here, Tn=2n+3 To find, T1, substitute n=1 in Tn=2n+3 T1=2(1)+3=2+3=5 To find T2, substitute n=2 in Tn=2n+3 T2=2(2)+3=4+3=7 Similarly, T3=2(3)+3=6+3=9 ∴ The first three terms of the sequence are 5,7,9.