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Emulsions

FIND THE FLUX...

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FIND THE FLUX THROUGH THE DISC DERIVATION

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Q. Find the flux through the circular disc due the point charge q.

Q. A circular disc of radius 𝑅 carries surface charge density

σ (r) = σ_{o} (1 - \frac{r}{R})

σ_{o}

is a constant and

r

is the distance from the center of the disc. Electric flux through a large spherical surface that encloses the charged disc completely is

ϕ_{0}

. Electric flux through another spherical surface of radius

\frac{R}{4}

and concentric with the disc is

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.Then the ratio

\frac{ϕ_{0}}{ϕ}

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σ

, the electric flux through the disc due to the point charge will be :

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