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Question

Find the focus of the parabola y=2(x+4)21.

A
(4,1)
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B
(4,98)
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C
(4,1)
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D
(4,98)
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Solution

The correct option is B (4,98)
Given, y=2(x+4)21
y+1=2(x+4)2(x+4)2=12(y+1)4a=12
a=18
The focus of x2=4ay is (0,a).
Let (h,k) be the focus of given parabola
h+4=0,k+1=18x=4,y=98
So, the focus is (4,98).
Option D is correct.

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