Find the following:
$(i)$ the first $15$ multiples of $8$ .
$(i i)$ the first $40$ positive integers divisible by $(a) 3 (b) 5 (c) 6$

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Solution

$(i)$ Multiples of $8, 8, 16, 24....8 n$
Where $n ϵ I, n ϵ [1, 15]$
$(i i) (a)$ Multiples of $33, 6, 9....3 n$
Where $n ϵ I, n ϵ [1, 40]$
$(b)$ Multiples of $5, 5, 10, 15...5 n$
Where $n ϵ I, n ϵ [1, 40]$
$(c)$ Multiples of $6, 6, 12, 18, 24....6 n$
Where $n ϵ I, n ϵ [1, 40]$

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Similar questions

Q. Find the sum of

(i) the first 15 multiples of 8

(ii) the first 40 positive integers divisible by (a) 3 (b) 5 (c) 6.

(iii) all 3 − digit natural numbers which are divisible by 13.

(iv) all 3 - digit natural numbers, which are multiples of 11.

Q. Find the sum of

(i) the first 15 multiples of 8

(ii) the first 40 positive integers divisible by (a) 3 (b) 5 (c) 6.

(iii) all 3 − digit natural numbers which are divisible by 13.

(iv) all 3 − digit natural numbers, which are multiples of 11.

(v) all 2 − digit natural numbers divisible by 4.

(vi) first 8 multiples of 3.

Find the sum of
(i) the first 15 multiples of 8
(ii) the first 40 positive integers divisible by (a) 3 (b) 5 (c) 6.
(iii) all 3-digit natural numbers, which are divisible by 13.
(iv) all 3-digit natural numbers, which are multiples of 11.
(v) all 2-digit natural numbers divisible by 4.

While learning I came across a question which was as follows:

Find the sum of the first 40 positive integers divisible by 6.

My doubt is that should I find the sum of the 1st 40 multiples of 6 or the multiples of 6 from starting from 1 to 40 (i.e, 6,12,18,24,30,36).

Find the sum of first 40 positive integers divisible by 6.

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Find the following:(i) the first 15 multiples of 8.(ii) the first 40 positive integers divisible by (a)3(b)5(c)6

(i) Multiples of 8,8,16,24....8nWhere nϵI,nϵ[1,15](ii)(a) Multiples of 33,6,9....3nWhere nϵI,nϵ[1,40](b) Multiples of 5,5,10,15...5nWhere nϵI,nϵ[1,40](c) Multiples of 6,6,12,18,24....6nWhere nϵI,nϵ[1,40]

Find the following:
$(i)$ the first $15$ multiples of $8$ .
$(i i)$ the first $40$ positive integers divisible by $(a) 3 (b) 5 (c) 6$

$(i)$ Multiples of $8, 8, 16, 24....8 n$
Where $n ϵ I, n ϵ [1, 15]$
$(i i) (a)$ Multiples of $33, 6, 9....3 n$
Where $n ϵ I, n ϵ [1, 40]$
$(b)$ Multiples of $5, 5, 10, 15...5 n$
Where $n ϵ I, n ϵ [1, 40]$
$(c)$ Multiples of $6, 6, 12, 18, 24....6 n$
Where $n ϵ I, n ϵ [1, 40]$