Find the following integrals. ∫(1−x)√xdx.
∫(1−x)√xdx=∫(√x−x32)dx=x(12)+1(12)+1−x(32)+1(32)+1+C=x(32)(32)−x(52)(52)+C(∴∫xndx=xn+1n+1)=23x32−25x52+C
Integrate the following functions. ∫1x−√xdx.