Find the following limit- limn - - x2 - 4x - 3-x2 - 3x - 4-

lim_x→∞x^2 4x+3x^2+3x 4=lim_x→∞(x 3)(x 1)(x+4)(x 1)=lim_x→∞x 3x+4=lim_x→∞1 3x1+4x=1 ...

You visited us 13 times! Enjoying our articles? Unlock Full Access!

Byju's Answer

Standard IX

Mathematics

Properties of Measures of Central Tendency

Find the foll...

Question

Find the following limit.
$lim n \to \infty \frac{x^{2} - 4 x + 3}{x^{2} + 3 x - 4} .$

Open in App

Solution

$lim x \to \infty \frac{x^{2} - 4 x + 3}{x^{2} + 3 x - 4} = lim x \to \infty \frac{(x - 3) (x - 1)}{(x + 4) (x - 1)} = lim x \to \infty \frac{x - 3}{x + 4} = lim x \to \infty \frac{1 - \frac{3}{x}}{1 + \frac{4}{x}} = 1$

Suggest Corrections

Similar questions

Q. Find the following limit.

lim x \to 2 \frac{x - \sqrt{3 x - 2}}{x^{2} - 4} .

Q. Find the following limit:

lim x \to \infty \frac{x^{2} + 3 x - 4}{1 - 3 x^{2}} .

Question 10
Which of the following equations has no real roots?
(A) $x^{2} - 4 x + 3 \sqrt{2} = 0$
(B) $x^{2} + 4 x - 3 \sqrt{2} = 0$
(C) $x^{2} - 4 x - 3 \sqrt{2} = 0$
(D) $3 x^{2} - 4 \sqrt{3} x + 4 = 0$

Q. Find the largest integral

x

which satisfies the following inequality:

\frac{x + 4}{x^{2} - 9} - \frac{2}{x + 3} < \frac{4 x}{3 x - x^{2}}

Q. Find:

{lim}_{n \to 0} \frac{\sqrt{1 + x^{2}} - \sqrt{1 - x + x^{2}}}{3^{x} - 1} =

Join BYJU'S Learning Program

Find the following limit.limn→∞x2−4x+3x2+3x−4.

limx→∞x2−4x+3x2+3x−4=limx→∞(x−3)(x−1)(x+4)(x−1)=limx→∞x−3x+4=limx→∞1−3x1+4x=1

Find the following limit.
$lim n \to \infty \frac{x^{2} - 4 x + 3}{x^{2} + 3 x - 4} .$

$lim x \to \infty \frac{x^{2} - 4 x + 3}{x^{2} + 3 x - 4} = lim x \to \infty \frac{(x - 3) (x - 1)}{(x + 4) (x - 1)} = lim x \to \infty \frac{x - 3}{x + 4} = lim x \to \infty \frac{1 - \frac{3}{x}}{1 + \frac{4}{x}} = 1$