Question

Find the following product:
−11a(3a + 2b)

Answer 1

To find the product, we will use distributive law as follows:

$$\begin{gathered} -11a\left(3a+2b\right) \\ =\left(-11a\right)\times 3a+\left(-11a\right)\times 2b \\ =\left(-11\times 3\right)\times \left(a\times a\right)+\left(-11\times 2\right)\times \left(a\times b\right) \\ =\left(-33\right)\times \left(a^{1+1}\right)+\left(-22\right)\times \left(a\times b\right) \\ =-33a^2-22ab \end{gathered}$$

Thus, the answer is $-33a^2-22ab$.