Question

Find the following product:
−11y²(3y + 7)

Answer 1

To find the product, we will use distributive law as follows:

$$\begin{gathered} -11y^2\left(3y+7\right) \\ =\left(-11y^2\right)\times 3y+\left(-11y^2\right)\times 7 \\ =\left(-11\times 3\right)\left(y^2\times y\right)+\left(-11\times 7\right)\times \left(y^2\right) \\ =\left(-33\right)\left(y^{2+1}\right)+\left(-77\right)\times \left(y^2\right) \\ =-33y^3-77y^2 \end{gathered}$$

Thus, the answer is $-33y^3-77y^2$.