Question

Find the following product by using suitable identity

$(3.29{)}^3+(6.71{)}^3$

• A. $137.763$
• B. $337.723$
• C. $7437.778$
• D. $237.233$

Answer 1

Answer: (B)

$337.723$

$(3.29{)}^3+(6.71{)}^3$
Using,$(a^3+b^3)=(a+b)(a^2-ab+b^2)$
$=(3.29+6.71)\left[\right(3.29{)}^2-\left(3.29\right)\left(6.71\right)+\left(6.71{)}^2\right]$
$=10(10.8241-22.0759+45.0241)$
$=10\left(33.7723\right)$
$=337.723$