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Question

Find the following product: (x32x2+5)×(4x1)

A
4x39x3+2x2+20x5
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B
4x49x3+2x2+20x5
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C
4x4+9x3+2x2+20x5
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D
4x49x32x2+20x5
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Solution

The correct option is D 4x49x3+2x2+20x5
Required product is (x32x2+5)×(4x1)
Multiplying the two polynomials, we get:
(x32x2+5)×(4x)(x32x2+5)×(1)
=4x48x3+20xx3+2x25
=4x49x3+2x2+20x5
Hence, (x32x2+5)×(4x1)=4x49x3+2x2+20x5.

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