Find the following sum 1-22-1-1-42-1-1-62-1- - -1-202-1

The correct option is B S = 1/2[1/1 1/3+1/3 1/5+.............. 1/19+1/19 1/21] =1/2[1 1/21]=10/21 ...

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Question

Find the following sum $\frac{1}{2^{2} - 1} + \frac{1}{(4^{2} - 1)} + \frac{1}{6^{2} - 1} + . . . . . + \frac{1}{20^{2} - 1}$

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\frac{1}{2^{2} - 1} + \frac{1}{4^{2} - 1} + \frac{1}{6^{2} - 1} + . . . . + \frac{1}{20^{2} - 1}

(\frac{1}{(2^{2} - 1)}) + (\frac{1}{(4^{2} - 1)}) + (\frac{1}{(6^{2} - 1)}) + . . . + (\frac{1}{(20^{2} - 1)})

[\frac{1}{(2^{2} - 1)}] + [\frac{1}{(4^{2} - 1)}] + [\frac{1}{(6^{2} - 1)}] + . . . . . . . . + [\frac{1}{(20^{2} - 1)}]

[\frac{1}{(2^{2} - 1)}] + [\frac{1}{(4^{2} - 1)}] + [\frac{1}{(6^{2} - 1)}] + . . . + [\frac{1}{(20^{2} - 1)}]

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