Question

Find the force acting at the pivoted end of the rod in terms of mass $m$ of the rod.

• A. $(\sqrt{2}-1)mg$
• B. $(\sqrt{2}+1)mg$
• C. $(\sqrt{3}+1)mg$
• D. $(\sqrt{2}+3)mg$

Answer 1

The correct option is A $(\sqrt{2}-1)mg$

Net force on pivoted end

$=(F_b-mg)$

$F_b=\rho \left(\frac{L}{\sqrt{2}}\right).g=\frac{\rho }{2}Lg\times \sqrt{2}=mg\sqrt{2}$

$F_{net}=mg(\sqrt{2}-1)$