Find the force exerted at the support S in terms of ‘m’ if the system shown is in equilibrium.
A
3mg
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B
2mg
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C
4mg
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D
5mg
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Solution
The correct option is C4mg FBDs of both pulleys and the body of mass m is as shown
Let the force exerted at the support S is F Then, from the equilibrium condition we have, From pulley 1, F=2T From pulley 2, T=2T′ And, from the body of mass m, T′=mg So, from above equations we have F=2T=2(2T′)=4T′=4mg