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Question

Find the force exerted at the support S in terms of ‘m’ if the system shown is in equilibrium.


A
3 mg
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B
2 mg
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C
4 mg
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D
5 mg
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Solution

The correct option is C 4 mg
FBDs of both pulleys and the body of mass m is as shown

Let the force exerted at the support S is F
Then, from the equilibrium condition we have,
From pulley 1, F=2T
From pulley 2, T=2T
And, from the body of mass m, T=mg
So, from above equations we have
F=2T=2(2T)=4T=4mg

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