Question

Find the force exerted by the water on a 2 m² plane surface of a large stone placed at the bottom of a sea 500 m deep. Does the force depend on the orientation of the surface?

Answer 1

Given:
Depth of the stone from the water surface, h = 500 m
Area of the plane surface of the large stone, A = 2 m²
Density of water, ρ_w = 10³ kgm^−3
​Force (F) is given by
$$\begin{gathered} F=P\times A=\left(h{\rho }_w\times g\right)A\left(P=\mathrm{Pressure}\right) \\ \Rightarrow F=\left(500\times {10}^3\times 10\right)\times 2 \\ ={10}^7\mathrm{N}/{\mathrm{m}}^2 \end{gathered}$$
The force does not depend on the orientation of the rock when the surface area of the stone remains the same.