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Question

Find the fourth term from the end in an A.P. –11, –8, –5,...., 49.

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Solution

The given sequence is –11, –8, –5,...., 49.

Here,
First term (a) = –11
Common difference (d) = 3
n = 4
Last term (l) = 49

We know that,
nth term from the end=l-n-1d4th term from the end=l-4-1d =49-33 =49-9 =40

Hence, the fourth term from the end is 40.

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