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Depression in Freezing Point

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Question

Find the freezing point of a solution containing 0.5 mole of glucose dissolved in 200 g of $H_{2} O$ ?(Given that $K_{f}$ for water is 1.86 $K m^{- 1}$ ).

- 4.65

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- 2.65

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- 14.65

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- 8.65

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Solution

The correct option is D $- 4.65$
$Δ T_{f} = K_{f} m$
$T_{f}^{0} - T_{f} = 1.86 \times (1000 \times 0.5 / 200)$
$100 - T_{f} = 1.86 \times 2.5$
$T_{f} = 100 - 4.65$
$T_{f} = 100 - 4.65$
here, depression in freezing point = $- 4.65$
and freezing point , $T_{f} = {95.35}^{o} C$

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