Find the frequency of light that correspond to photons energy $5.0 \times 10^{- 5}$ erg:

2.2 \times 10^{11} s e c^{- 1}

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7.5 \times 10^{21} s e c^{- 1}

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4.0 \times 10^{- 5} s e c^{- 1}

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4.0 \times 10^{4} s e c^{- 1}

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Solution

The correct option is B $7.5 \times 10^{21} s e c^{- 1}$

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When a certain metal was irradiated with light of frequency $4.0 \times 10^{16} s^{- 1}$ , the photoelectrons emitted had three times the kinetic energy as the kinetic energy of photoelectrons emitted when the metal was irradicated with light of frequency $2.0 \times 10^{16} s^{- 1}$ . Calculate the critical frequency ( $ν_{0}$ ) of the metal.

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Find the frequency of light that correspond to photons energy 5.0×10−5 erg:

The correct option is B 7.5×1021sec−1

Find the frequency of light that correspond to photons energy $5.0 \times 10^{- 5}$ erg:

The correct option is B $7.5 \times 10^{21} s e c^{- 1}$