Question

Find the frequency of minimum distance between compression $\&$ rarefaction of a wire. If the length of the wire is $1m\&$ velocity of sound in air is $360m/s$

• A. 90s
• B. 180s
• C. 120s
• D. 360s

Answer 1

Answer: (A)

90s

(a) The minimum distance between compression and rarefaction of the wire $l=\frac{\lambda }{4}\therefore$ Wave length $\lambda =4l$
Now by $v=n\lambda \Rightarrow n=\frac{360}{4\times 1}=90{sec}^{-1}$