Find the frictional force between the two blocks. Take g=10m/s2.
A
6N
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B
28N
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C
30N
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D
70N
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Solution
The correct option is A6N By FBD, In y - direction, N1=3g fmax=μN1=(0.2)(3g) =6N
Assume them to move together with common acceleration, ac=Fm1+m2=4010=4m/s2
For 7kg body: f=7ac=28N is required to make them move together, which is not possible because maximum force supplied by friction is fmax which is equal to 6N. Hence the blocks moves seperately and the friction is kinetic in nature and equals to limiting friction in this case.