Find the frictional force $f$ in each case

Open in App

Solution

$\frac{m g s i n θ - F}{m} = a, \frac{F R}{m K^{2}} = α R α = a \Rightarrow m g s i n θ - F = \frac{F R^{2}}{K^{2}} \Rightarrow F (1 + \frac{R^{2}}{K^{2}}) = m g s i n θ f o r s p h e r e \frac{R^{2}}{K^{2}} = \frac{5}{2} f o r d i s c \frac{R^{2}}{K^{2}} = 2 f o r l o o p \frac{R^{2}}{K^{2}} = 1 ∴ f o r s p h e r e F = \frac{2 m g s i n θ}{7} = 4.2 N f o r d i s c F = \frac{m g s i n θ}{3} = 4.9 N f o r h o o p F = \frac{2 m g s i n θ}{2} = 7.35 N$

Suggest Corrections

Similar questions

Determine the magnitude of frictional force in each of the following cases:

m

v

F

f

I

Join BYJU'S Learning Program