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Question

Find the GCD of the following x2+14x+33,x3+10x2−11x

A
x+11
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B
x11
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C
x+112
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D
None of these
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Solution

The correct option is A x+11
We first factorize the given polynomials x2+14x+33 and x3+10x211x as shown below:

x2+14x+33=x2+3x+11x+33=x(x+3)+11(x+3)=(x+3)(x+11)

x3+10x211x=x(x2+10x11)=x(x2x+11x11)=x[x(x1)+11(x1)]=x(x1)(x+11)

The common factor of x2+14x+33 and x3+10x211x is (x+11), therefore, the GCD is x+11.

Hence, the greatest common divisor of x2+14x+33 and x3+10x211x is x+11.

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