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Byju's Answer
Standard XII
Mathematics
Roots of a Quadratic Equation
Find the gene...
Question
Find the general solution and the least positive integral solution of
455
x
−
519
y
=
1
.
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Solution
455
x
−
519
y
=
1
−
64
y
+
455
(
x
−
y
)
=
1
⟹
−
64
y
+
455
z
=
1
where
z
=
x
−
y
⟹
−
64
y
+
(
64
×
72
+
7
z
)
=
1
⟹
72
−
64
(
y
−
7
z
)
=
1
⟹
7
z
−
64
t
=
1
where
t
=
y
−
7
z
⟹
7
z
−
(
7
×
9
t
+
t
)
=
1
⟹
−
t
+
7
(
z
−
9
t
)
=
1
−
t
+
7
u
=
1
where
u
=
z
−
9
t
t
h
e
n
u
=
0
,
∴
t
=
−
1
u
=
z
−
9
t
gives
z
=
−
9
t
=
y
−
7
z
gives
y
=
−
64
z
=
x
−
y
gives
x
=
−
73
∴
Solutions are given by
x
=
−
73
+
519
k
y
=
−
64
+
455
k
,
where
k
=
1
,
the least positive integral solution is
x
=
446
,
y
=
391
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