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Question

Find the general solution for each of the following equation:
sin2x+cosx=0

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Solution

Given sin2x+cosx=0

2sinxcosx+cosx=0

(2sinx+1)cosx=0

(2sinx+1)=0 or cosx=0

sinx=12 or cosx=0

x=7π6+2nπ,x=11π6+2nπ or x=±π2+2nπ (Since, sin is negative in third and fourth quadrant)

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