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Question

Find the general solution for the following equation:

cos 4x = cos 2x

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Solution

Here cos= 4x = cos 2x

4x=2nπ± 2x, n ϵ Z

[ If cos x = cos y x=2nπ± y]

4x2x=2nπ or 4x + 2x = 2nπ,nϵ Z

2x=2nπ or 6x = 2nπ,nϵZ

x=2π or x=nπ3,n ϵ Z

Hence general solutions are nπ or nπ3,n ϵ Z.


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