Find the general solution for the following equation:
cos 4x = cos 2x
Here cos= 4x = cos 2x
⇒4x=2nπ± 2x, n ϵ Z
[∵ If cos x = cos y ⇒x=2nπ± y]
⇒4x−2x=2nπ or 4x + 2x = 2nπ,nϵ Z
⇒2x=2nπ or 6x = 2nπ,nϵZ
⇒x=2π or x=nπ3,n ϵ Z
Hence general solutions are nπ or nπ3,n ϵ Z.