Find the general solution of 2sin 3x -1 =0

$x = n π + (- 1)^{n} \frac{π}{18}$

No worries! We‘ve got your back. Try BYJU‘S free classes today!

$x = \frac{n π}{3} + (- 1)^{n} \frac{π}{18}$

No worries! We‘ve got your back. Try BYJU‘S free classes today!

$x = n π + (- 1)^{n} \frac{π}{6}$

No worries! We‘ve got your back. Try BYJU‘S free classes today!

$x = \frac{n π}{3} + (- 1)^{n} \frac{π}{18}$

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

Open in App

Solution

The correct option is D
$x = \frac{n π}{3} + (- 1)^{n} \frac{π}{18}$

$2 s i n 3 x - 1 = 0 s i n 3 x = \frac{1}{2} 3 x = n π + (- 1)^{n} \frac{π}{6} x = \frac{n π}{3} + (- 1)^{n} \frac{π}{18}$

Suggest Corrections

Similar questions

2 tan x - cot x + 1 = 0

Find the general solution of the equation 4 sin x cos x + 2 sin x + 2 cos x +1 = 0.

sin 2 x + sin 4 x = 2 sin 3 x

0 \leq x \leq π

4 {sin}^{2} x - 8 cos x + 1 = 0

y = 2 sin 3 x

\frac{d^{2} y}{d x^{2}} + 9 y = 0

Join BYJU'S Learning Program