Question

Find the general solution of given line $9x-3y=9$ and $3x-y=3$

Answer 1

The two given lines are $3x-y=3$ and $9x-3y=9$

Now dividing second line by $3$ we get $3x-y=3$

so $L_{1}and{L}_2$ are identical lines

so general solution of the lines is $(\alpha ,3\alpha -3)$