Question

Find the general solution of the differential equation:
$xdy-ydx=\sqrt{x^2+y^2}dx$

Answer 1

$xdy-ydx=\sqrt{x^2+y^2}dx⟹xdy=(y+\sqrt{x^2+y^2})dx⟹(y+\sqrt{x^2+y^2})=c{x}^2$