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Question

Find the general solution of the differential equation y=px+p2 where p=dydx

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Solution

Given the differential equation is y=px+p2.
Now differentiating both sides with respect to x we get,
p=p+{x+2p}dpdx [ Since p=dydx]
or, dpdx=0 and x+2p=0
or, p=c......(1)[ Where c is integrating constant] and x+2p=0......(2).
Equation (1) will lead us to a general solution and equation (2) will lead us singular solution.
So the general solution is y=cx+c2. [ putting p=c in the given differential equation]

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