Find the general solution of the equation sin7θ=sin3θ+sinθ
We will try to simplify the terms using the transformation formula. For that we will take sinθ to L.H.S.
We do this expecting that we get one sin3θ after simplifying.
⇒sin7θ−sinθ=sin3θ
⇒2 sin 3 θ cos 4 θ=sin3θ
sin3θ = 0 or cos4θ = 1/2
⇒3θ=nπ or 4θ=2nπ±π3
⇒θ=nπ3 or θ=nπ2±π12