Find the general solutions of 3 tan 2 x -1-0A- x - n -6B - x - n -6C- x-n -3D- x-n -3

The correct options are A x=n π+π/6 B x=n π π/6 3tan^2x 1=0 tan^2x = 1/3 tan x=±1/√(3) x=n π+π/6 or n π π/6 ...

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Byju's Answer

Standard XI

Mathematics

Equations of the form acos?+bsin? = c

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Question

Find the general solutions of $3 t a n^{2} x - 1 = 0$

$x = n π + \frac{π}{6}$

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$x = n π - \frac{π}{6}$

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$x = n π + \frac{π}{3}$

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$x = n π - \frac{π}{3}$

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Solution

The correct options are
A
$x = n π + \frac{π}{6}$

B
$x = n π - \frac{π}{6}$

$3 t a n^{2} x - 1 = 0 t a n^{2} x = \frac{1}{3} t a n x = \pm \frac{1}{\sqrt{3}} x = n π + \frac{π}{6} o r n π - \frac{π}{6}$

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The general solution of $t a n 2 x = - c o t (x + \frac{π}{3}) i s (n ϵ Z)$

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Find the general solutions of 3tan2x−1=0

The correct options are A x=nπ+π6 B x=nπ−π6 3tan2x−1=0tan2x=13tan x=±1√3x=nπ+π6 or nπ−π6

Find the general solutions of $3 t a n^{2} x - 1 = 0$

The correct options are
A
$x = n π + \frac{π}{6}$

B
$x = n π - \frac{π}{6}$

$3 t a n^{2} x - 1 = 0 t a n^{2} x = \frac{1}{3} t a n x = \pm \frac{1}{\sqrt{3}} x = n π + \frac{π}{6} o r n π - \frac{π}{6}$