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Question

Find the general term (nth term) and 23th term of the sequence 3,1,1,3,..

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Solution

3,1,1,3
=>a=3
=>d=13=2
=>t23=a(n1)d
=3+(231)(2)
=3+(22)(2)
=>344=41
=>tn=3+(n1)(2)
=32n+2
=52n


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