Find the general term of a sequence, whose sum of n terms is given by $4 n^{2} + 3 n$ .

8 n + 1

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4 n - 2

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8 n - 1

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4 n - 1

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Solution

The correct option is C $8 n - 1$
We can find $T_{n}$ by calculating $S_{n} - S_{n - 1}$
So, $T_{n} = 4 n^{2} + 3 n - (4 (n - 1)^{2} + 3 (n - 1)) = 4 n^{2} + 3 n - 4 (n - 1)^{2} - 3 (n - 1)$
$= 4 n^{2} + 3 n - 4 n^{2} - 4 + 8 n - 3 n + 3 = 8 n - 1$

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