Find the gravitational attraction between the two atoms in a hydrogen molecule- Given that G-6-67- 10-11 Nm2 kg2- mass of a hydrogen atom -1-67- 10-27 kg and distance between the two atoms -1oA-

Here, G=6.67× 10^ 11 N m^2 kg^2 M_1=M_2=1.67× 10^ 27kg; r=1A^o=10^ 10m Now, F=GM_1M_2r^2 =6.67× 10^ 11× 1.67× 10^ 27× 1.67× 10^ 27(10^ ...

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Standard IX

Physics

Universal Law of Gravitation

Find the grav...

Question

Find the gravitational attraction between the two atoms in a hydrogen molecule. Given that $G = 6.67 \times 10^{- 11} N m^{2} k g^{2}$ , mass of a hydrogen atom $= 1.67 \times 10^{- 27}$ kg and distance between the two atoms $= 1^{o} A .$

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Solution

Here, $G = 6.67 \times 10^{- 11} N m^{2} k g^{2}$
$M_{1} = M_{2} = 1.67 \times 10^{- 27} k g;$
$r = 1 A^{o} = 10^{- 10} m$

Now, $F = G \frac{M_{1} M_{2}}{r^{2}}$

$= \frac{6.67 \times 10^{- 11} \times 1.67 \times 10^{- 27} \times 1.67 \times 10^{- 27}}{(10^{- 10})^{2}}$
$= 1.86 \times 10^{- 44} N$

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State the universal law of gravitation. The mass of the electron and proton in a Hydrogen atom is given by $9 \times 10^{- 31} k g$ and $1.9 \times 10^{- 27} k g$ respectively which is separated by a distance $6 \times 10^{- 11} m$ . Calculate the gravitational force of attraction between them? [3 MARKS]

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Find the gravitational attraction between the two atoms in a hydrogen molecule. Given that G=6.67×10−11Nm2kg2, mass of a hydrogen atom =1.67×10−27 kg and distance between the two atoms =1oA.

Here, G=6.67×10−11Nm2kg2M1=M2=1.67×10−27kg;r=1Ao=10−10mNow, F=GM1M2r2=6.67×10−11×1.67×10−27×1.67×10−27(10−10)2=1.86×10−44N

Find the gravitational attraction between the two atoms in a hydrogen molecule. Given that $G = 6.67 \times 10^{- 11} N m^{2} k g^{2}$ , mass of a hydrogen atom $= 1.67 \times 10^{- 27}$ kg and distance between the two atoms $= 1^{o} A .$

Here, $G = 6.67 \times 10^{- 11} N m^{2} k g^{2}$
$M_{1} = M_{2} = 1.67 \times 10^{- 27} k g;$
$r = 1 A^{o} = 10^{- 10} m$

Now, $F = G \frac{M_{1} M_{2}}{r^{2}}$

$= \frac{6.67 \times 10^{- 11} \times 1.67 \times 10^{- 27} \times 1.67 \times 10^{- 27}}{(10^{- 10})^{2}}$
$= 1.86 \times 10^{- 44} N$