Question

Find the gravitational force between the two atoms in a hydrogen molecule. Given that $G=6.67\times {10}^{-11}N{m}^{2}k{g}^{-2}$, mass of a hydrogen atom $=1.67\times {10}^{-27}kg$ and distance between the two atoms $=1^{\circ }A$

• A. $2.86\times {10}^{-34}N$
• B. $3.86\times {10}^{-34}N$
• C. $1.86\times {10}^{-34}N$
• D. $1.86\times {10}^{-14}N$

Answer 1

The correct option is C $1.86\times {10}^{-34}N$

Given,

Gravitational constant $G=6\cdot 67\times {10}^{-11}N{m}^2{kg}^{-2}$

Mass of hydrogen atom $m_1=m_2=1\cdot 67\times {10}^{-27}kg$

Distance between the two atoms $r=1A^o={10}^{-10}m$

$\therefore F=\frac{{Gm}_1{m}_2}{r^2}=\frac{{6\cdot 67\times 10}^{-11}\times {1\cdot 67\times 1\cdot 67\times 10}^{-27}{\times 10}^{-27}}{{10}^{-10}\times {10}^{-10}}$

$F=1\cdot 86\times {10}^{-34}N$