Question

Find the gravitational force between two atoms in a hydrogen molecule. Given that $G=6.67\times {10}^{-11}N{m}^{2}k{g}^{-2}$ and mass of hydrogen atom $1.67\times {10}^{-27}kg$ and the distance between the two atoms$1^{o}A.$.The answer is $1.86\times {10}^{-xy}N$ then x+y =

Answer 1

The force of gravitation is given as

$F=\frac{G{m}_1{m}_2}{r^2}$

Given

$G=6.67\times {10}^{-11}N{m}^2/k{g}^2$

$m_1=1.67\times {10}^{27}$

$m_2=1.67\times {10}^{-27}kg$

$r=1A={10}^{-10}m$

so,

$F=\frac{[6.67\times {10}^{-11}\times 1.67\times {10}^{27}\times 1.67\times {10}^{27}]}{({10}^{-10}{)}^2}$

or,

=$\frac{1.860\times {10}^{64}}{{10}^{-20}}$

thus we get,

$F=1.86\times {10}^{-44}N$