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Question

Find the greatest and the least values of the following functions.
f(x)=3x39x2+2 on the interval [1,4].

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Solution

f(x)=3x39x2+2
f(x)=9x218x=0
x=0,2
f′′(x)=18x18
f′′(0)=18<0 Hence f(0)=2 is maximum
f′′(2)=18>0 Hence f(2)=10 is minimum

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