Find the greatest common factor of $- 4 a^{3} b^{2}, 12 a^{2} b^{3}, 16 a^{5} b c, 4 a^{2} b^{2}$ .

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Solution

$- 4 a^{3} b^{2} = - 2 \times 2 \times a \times a \times a \times b \times b$
$12 a^{2} b^{3} = 2 \times 2 \times 3 \times a \times a \times b \times b \times b$
$16 a^{5} b c = 2 \times 2 \times 2 \times 2 \times a \times a \times a \times a \times a \times b \times c$
$4 a^{2} b^{2} = 2 \times 2 \times a \times a \times b \times b$
Taking the common monomial, we get $2 \times 2 \times a \times a \times b$ = $4 a^{2} b$ .
Thus, the greatest common factor of $- 4 a^{3} b^{2}, 12 a^{2} b^{3}, 16 a^{5} b c, 4 a^{2} b^{2}$ $=$ $4 a^{2} b$ .

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