Find the greatest fraction:

$\frac{6}{7}$

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$\frac{3}{7}$

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$\frac{4}{7}$

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$\frac{2}{7}$

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Solution

The correct option is A
$\frac{6}{7}$

$\frac{6}{7}, \frac{3}{7}, \frac{4}{7}, \frac{2}{7}$
Since these are like fractions, we can just compare the numerator.
Hence, $\frac{6}{7}$ is the greatest fraction in the given list.

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Similar questions

1 + \frac{4}{7} + \frac{9}{7^{2}} + \frac{16}{7^{3}} + \frac{25}{7^{4}} + . . . . . .

\frac{1}{7} + \frac{2}{7^{2}} + \frac{1}{7^{3}} + \frac{2}{7^{4}} + . . .

1 + \frac{4}{7} + \frac{9}{7^{2}} + \frac{16}{7^{3}} + \frac{25}{7^{4}} + \dots upto \infty

\frac{4}{7} - \frac{5}{7^{2}} + \frac{4}{7^{3}} - \frac{5}{7^{4}} + \frac{4}{7^{5}} - \frac{5}{7^{6}} + . . . .

\frac{1}{7} + \frac{2}{7^{2}} + \frac{1}{7^{3}} + \frac{2}{7^{4}} + . . . .

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