Find the greatest length of an organ pipe open at both ends that will have its fundamental frequency in the normal hearing range (20-20,000 Hz). Speed of sound in air = 340ms−1.
Let the length will be I.
Here given that,
V=340 m/s
and n =20 Hz
Here λ2=2I
We know, v=nλ
⇒I=V2×n=3402×20
=344=8.5cm
(for maximum wavelength the frequency is minimum)