Find the greatest number of 5 digits which is exactly divisible by 20,24,35 and 45.
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Solution
First of all we will find the L.C.M of 20, 24, 35 45. So, L.C.M= 2×2×5×3×2×7×3 = 1520. Greatest 5 digit number= 99999. We will divide 99999 by 1520 and find the remainder.
99999÷ 1520= Q= 65 R= 1199.
A.T.Q we need a greatest 5 digit no. exactly divisible by 1520.
Therefore, the required number is 99999-1199= 98800