Question

Find the greatest number of five digits which when divided by $3,5,8,12$ will have $2$ as remainder.

• A. $99999$
• B. $99958$
• C. $99960$
• D. $99962$

Answer 1

The correct option is D $99962$

Greatest number of $5$ digits $=99999.$
L.C.M of $3,5,8$ and $12.$
$=2\times 2\times 3\times 5\times 2$
$=120$
Dividing $99999$ by $120$ the remainder $=39$
$\therefore$ Required number $=(99999-39)+2$

$=99960+2=99962$