Find the greatest number of four digits which when divided by 10,11,15, and 22 leaves 3,4,8 and 15 as remainders?
A
9907
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B
9903
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C
9893
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D
9903
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Solution
The correct option is C 9893 Here its better to evaluate the options a) 9907 When divided by 10, it leaves a remainder 7 but we want remainder 3. Thus out
b) 9903 When divided by 10, it leaves a remainder 3. ok When divided by 11, it leaves a remainder 3 but we want remainder 4. Thus out
c) 9893 When divided by 10, it leaves a remainder 3. ok When divided by 11, it leaves a remainder 4. ok When divided by 15, it leaves a remainder 8. ok When divided by 22, it leaves a remainder 15. ok Answer(c)