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Question

Find the greatest number of four digits which when divided by 10,11,15, and 22 leaves 3,4,8 and 15 as remainders?

A
9907
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B
9903
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C
9893
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D
9903
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Solution

The correct option is C 9893
Here its better to evaluate the options
a) 9907
When divided by 10, it leaves a remainder 7 but we want remainder 3. Thus out

b) 9903
When divided by 10, it leaves a remainder 3. ok
When divided by 11, it leaves a remainder 3 but we want remainder 4. Thus out

c) 9893
When divided by 10, it leaves a remainder 3. ok
When divided by 11, it leaves a remainder 4. ok
When divided by 15, it leaves a remainder 8. ok
When divided by 22, it leaves a remainder 15. ok
Answer(c)

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